in. 314.16(B)(4) requires a double volume allowance based on the size of wire connected to the device - #12 wire being 2.25 cu. 35 x 106.25 = 141.25A. You’ll be amazed at how often your electrical studies return to the basics of this unit. Table 314.16(B) shows an allowance of 2.25 cu. in. Using Ch.9 Table 5, you find the following wire area numbers: #500 kcmil THWN = 0.7073", 314.28(A)(1) requires 8x the largest raceway minimum: 8 x 3" = 24". The wire resistance is found in Ch. As most students of mathematics have encountered, when the subject of systems of equations is introduced, math class is temporarily converted into a crash course in electrical components. To determine how many receptacles are permitted to be connected to a circuit, first find the VA of the circuit (volts x amperes) and divide the result by 180 VA. This unit includes math and electrical fundamentals. in. 8.6kw ÷ 240V = 35.8A. From 310.15(B)(16) we find these wires have an ampacity of 25, therefore: 25A x 80% = 20A. 314.28(A)(2) states that the distance from the raceway entry to the opposite side of the box shall not be less than 6 times the size of the largest conduit. Efficiency What is the power output of kettle 2 kW with efficiency 90%? as per Table 314.16(B). Ch. Electrical engineering - math word problems Electrical engineering is an engineering discipline that generally deals with the study and application of electricity, electronics, and electromagnetism. For this environment, Table 352.44 shows a length change of 3.04"/100'. Quality starts with who wrote the material. Refer to Section 210.62. Here it refers you to the appropriate Tables in Ch. note 2 shows the need to maintain the voltage drop to less than 3%. Chapter 1 Introduction 1.1Themes1 From its beginnings in the late nineteenth century, electrical engineering has blossomed from focusing on electrical circuits for power, telegraphy and telephony to focusing on a much broader range of disciplines. Most states require an electrician to pass an exam to receive a journeyman or master electrician license. 1. 240.4(B) allows you to use the next size up if ampacity is not equal to a standard size, therefore this wire can be connected to a 100 breaker. required, subtracting the available 21 cu. 9, you will need to use Tables 1, 4, and 5 for the following numbers: #14 = 0.0097 circ. �?Ԩ��l*tҨ���¬��PEJ����6���2��xb�>D`)�h��ܼ����� ��1%���^��F���c�-�-�s��w���L�F"�u������n�Z]CdQD�ƼG minimum to be accommodated with the plaster ring. Section 220.14(I) requires receptacles on a single strap to be considered a load of 180 VA each. mil: 0.0097 x 132 = 1.2804, 0.0133 x 5 = 0.0665, 1.2804 + 0.0665 = 1.3469". Ch. State exams cover such areas as power and current formulas, branch circuit load calculations, voltage drop, raceway fill and sizing and more. Take a free Electrician Math Practice Test to see what kind of math questions are on actual electrician license exams. Then apply the single-phase voltage-drop formula as follows: Table 310.15 (B)(2)(a) shows that a correction factor multiplier of 0.65 applies to this environment. Per Table 310.15(B)(16), #1/0 would be sufficient for 150A, that was increased to #350 kcmil. 6 x 1.5" = 9". To prevent the use of floor receptacles and extension cords, receptacles are required to be installed directly above a show window. 725.51(A) refers you to 300.17, which directs you to refer to the appropriate wiring method section of the NEC. Thus. from the previous question, equals 8.25 cu. Table 250.122 shows a #6 required; 250.122(B) states that if the ungrounded conductors are increased in size, the ECG must be increased proportionately. Copyright © 2009-2020 Tests.com LLC - All Rights Reserved. 9 Table 8 gives the conductor circular mil area, for a #3/0 - 167,800, a #3 - 52,620. Below is a list of math used in electrical engineering: Algebra. 210.19(A)(4) requires an ampacity sufficient for the load served, and as a non-commercial cooking facility, in a classroom setting, the continuous load rating would not apply. With 24.75 cu. To solve this problem, first find the temperature adder, 40ºF, from Table 310.15(B)(3)(c) due to the proximity of the conduit to the rooftop exposure to sunlight then, add this value to the outdoor ambient temperature: 352.44 states that an expansion coupling is needed if the conduit will change more than 1/4" in length in a straight run. 725.51(B)(1,2) clarifies that the adjustment factors of 310.15(B)(3)(a) apply only to the power supply conductors, which would be an 80% adjustment factor. The calculation for 80 continuous feet of show window is as follows: 250.122(B) requires the EGC to be increased proportionately to the ungrounded conductors. Inf. A prospective engineering student must be able to solve variable equations and understand how to factor complex polynomial expressions. Please choose another answer. 9 Table 8 gives the circular mil area of #1/0 to be 105,600. Adding 2 x 2.25 = 4.5 cu.in., added to the 3.75 cu. To determine ratio: 350,000 ÷ 105,600 = 3.314. H��W��(���� Number of problems found: 38. Problem-solving skills. in. in. %PDF-1.2 %���� 11 0 obj << /Length 12 0 R /Filter /FlateDecode >> stream %PDF-1.7 %���� Circular mil area of #6 is 26,240, so applying the ratio = 26,240 x 3.314 = 86,959 circ. Transformer Transformer - U1 = 230 V, N1 = 300, N2 = 1,200, I1 = 4 A. in. Table 250.122 gives the EGC size for a 400a feed to be a #3 cu wire. To determine the voltage-drop, first find the circular mil area of the conductors as shown in Chapter 9, Table 8. Ohm’s law and the electrical formulas related to it are the foundation of all electrical circuits. ���B]=L1�������X�D�v��g# Table 310.15(B)(3)(a) shows an 80% adjustment factor needing to be applied, Table 310.15(B)(16) shows #2 THWN having an ampacity of 115A: 115A x 80% = 92A. h�b```���\�� cc`a�x-���$1�d.��X������V(W2Z\��Ҳe���?yI� �]&����l� �Y� �o��400L]�5)G6+h��eGv��f@\M�'4E���_N3[&:���E�VS���iKB��6(�v. In this case, you would use 358.22. Table 310.15(B)(16) shows that a #6 THWN-2 copper conductor is rated for 75 amps, therefore: 75 x 0.65 = 48.75A. in./ #12. Regardless of their discipline, engineers are, at their core, problem solvers.This is particularly true in electrical engineering, where you are often required to think logically and apply a particular rule or concept to a problem in order to solve it.. Electrical Engineering. H�E�A�0EO0w�KܔvJ.1h�q� S��Ą��6$�'���͗� 6�:9�/ in. Even though the breaker and wiring will be rated at 40 amperes, the minimum ampacity needed is 36A. �L?�,� endstream endobj 12 0 obj 150 endobj 9 0 obj << /Type /XObject /Subtype /Image /Name /I1 /Filter /FlateDecode /Width 433 /Height 287 /BitsPerComponent 4 /ColorSpace [ /Indexed /DeviceRGB 15 8 0 R ] /Length 10 0 R >> stream The basic algebra students learn in high school is only the beginning, a necessary foundation for almost any further development in either mathematics or electrical engineering. \�kz�U�Pɣۥ�A%��%`d�ly�D�:��Q�N�~-8h3�тԑ�w��ӭ�~���[��I�b)[Ϡc���6b�����j� Table 314.16(A) shows the box having a capacity of 21 cu. Using the resistance from #350 kcmil: 2 x 245' x 0.0382 x 141.25A = 2643.9175 ÷ 1000 = 2.643V, just under the 3V maximum. You must be very … One receptacle is required for every 12 linear ft. or "major fraction thereof" (6 ft. or more). (���f:�޲;�%�%���/���r�|{?#L p!|w� For help with math calculations on electrician license exams, the following two books written by Ray Holder (Master Electrician and Certified Electrical Trade Instructor) focus on math and show you, in a step-by-step way, how to solve electrician math problems: To solve this problem apply the single-phase current formula: I = P ÷ E. Incorrect answer. 1642 0 obj <> endobj 1675 0 obj <>/Filter/FlateDecode/ID[<582E4CE8D80D4F869FDBAC0E86C9208E><4E1F775DA6F54E7C8AF74F585F379F51>]/Index[1642 65]/Info 1641 0 R/Length 134/Prev 1389517/Root 1643 0 R/Size 1707/Type/XRef/W[1 2 1]>>stream State exams cover such areas as power and current formulas, branch circuit load calculations, voltage drop, raceway fill and sizing and more.